Topic 1. Stoichiometric relationships
![Screen Shot 2022-04-11 at 12.49.35 PM.png](https://static.wixstatic.com/media/2b3baf_41d7ea52c3f34141abf9f9adb67958f3~mv2.png/v1/fill/w_400,h_132,al_c,q_85,usm_0.66_1.00_0.01,enc_avif,quality_auto/Screen%20Shot%202022-04-11%20at%2012_49_35%20PM.png)
![Screen Shot 2022-04-11 at 12.50.17 PM.png](https://static.wixstatic.com/media/2b3baf_48d2c485ea294c388ec767e20279be5c~mv2.png/v1/fill/w_555,h_292,al_c,q_85,usm_0.66_1.00_0.01,enc_avif,quality_auto/Screen%20Shot%202022-04-11%20at%2012_50_17%20PM.png)
![Screen Shot 2022-04-11 at 12.50.08 PM.png](https://static.wixstatic.com/media/2b3baf_f7f92fb53d44470c8a78fad1f508f34b~mv2.png/v1/fill/w_400,h_210,al_c,q_85,usm_0.66_1.00_0.01,enc_avif,quality_auto/Screen%20Shot%202022-04-11%20at%2012_50_08%20PM.png)
Element V.S. Atom V.S. Compound V.S. Mixture
Element: composed of atoms that all have the same atomic number
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ex. carbon
Atom: the smallest unit of matter
Compound: 2+ elements that are chemically bonded
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ex. H2O, CO2
Mixture: 2+ elements/compounds that are not chemically bonded
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homogeneous mixtures have uniform properties
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heterogeneous mixtures have non-uniform properties
![IMG_3402.jpg](https://static.wixstatic.com/media/2b3baf_33fe88dd84514d9bbdad56749ce8c222~mv2.jpg/v1/fill/w_887,h_617,al_c,q_85,usm_0.66_1.00_0.01,enc_avif,quality_auto/IMG_3402.jpg)
From Ms. Fu's powerpoint
![Screen Shot 2022-04-11 at 1.19.46 PM.png](https://static.wixstatic.com/media/2b3baf_d876e3e3739c4b6fab5713693ec97c9c~mv2.png/v1/fill/w_619,h_388,al_c,q_85,usm_0.66_1.00_0.01,enc_avif,quality_auto/Screen%20Shot%202022-04-11%20at%201_19_46%20PM.png)
Compounds
Molar mass
Molar mass can be defined as the mass in 1 mol → unit is g/mol
Calculating relative atomic mass
Relative atomic mass (Ar) is the sum of the weighted average of the atomic mass of the known isotopes of an element.
![Screen Shot 2022-04-11 at 1.33.54 PM.png](https://static.wixstatic.com/media/2b3baf_97f99db6801a488fbc0e94672ef779ce~mv2.png/v1/fill/w_401,h_75,al_c,q_85,usm_0.66_1.00_0.01,enc_avif,quality_auto/Screen%20Shot%202022-04-11%20at%201_33_54%20PM.png)
Example question:
![IMG_3403.jpg](https://static.wixstatic.com/media/2b3baf_f63ee85d69c34bef85c8ac7082228547~mv2.jpg/v1/fill/w_506,h_178,al_c,q_80,usm_0.66_1.00_0.01,enc_avif,quality_auto/IMG_3403.jpg)
From smashingscience.org
0.7860*24 + 0.1011*25 + 0.1129*26 = 24.33
Ideal Gas Law
![IMG_3451.jpg](https://static.wixstatic.com/media/2b3baf_011bd8d4d89640e0828eac5056737fe3~mv2.jpg/v1/crop/x_0,y_85,w_1546,h_315/fill/w_599,h_122,al_c,q_80,usm_0.66_1.00_0.01,enc_avif,quality_auto/IMG_3451.jpg)
The units kPa and dm³ go together
The units Pa and m³ go together.
![Screen Shot 2022-04-11 at 1.41.24 PM.png](https://static.wixstatic.com/media/2b3baf_bd3d2b98c50d433b81fccbca46c7dd47~mv2.png/v1/fill/w_619,h_309,al_c,q_85,usm_0.66_1.00_0.01,enc_avif,quality_auto/Screen%20Shot%202022-04-11%20at%201_41_24%20PM.png)
Avogadro's Law states that the number of gaseous moles is proportional to the volume of the gas.
Gases behave more like ideal gases in low pressures (no attraction) and high temperatures.
![Screen Shot 2022-04-11 at 1.21.39 PM.png](https://static.wixstatic.com/media/2b3baf_49770bac3d41453885b94990b68b0361~mv2.png/v1/fill/w_619,h_178,al_c,q_85,usm_0.66_1.00_0.01,enc_avif,quality_auto/Screen%20Shot%202022-04-11%20at%201_21_39%20PM.png)
Stoichiometric relationships (very important)
![Screen Shot 2022-04-11 at 1.50.11 PM.png](https://static.wixstatic.com/media/2b3baf_80bc79703f204527b030130fafb2503c~mv2.png/v1/fill/w_599,h_287,al_c,q_85,usm_0.66_1.00_0.01,enc_avif,quality_auto/Screen%20Shot%202022-04-11%20at%201_50_11%20PM.png)
When solving problems about complete combustion, knowing this equation comes in handy.
![Screen Shot 2022-04-11 at 1.50.16 PM.png](https://static.wixstatic.com/media/2b3baf_51e5816960194533a8c67b65537481c2~mv2.png/v1/fill/w_463,h_51,al_c,q_85,usm_0.66_1.00_0.01,enc_avif,quality_auto/Screen%20Shot%202022-04-11%20at%201_50_16%20PM.png)
Deriving density from PV=nRT
![IMG_3404.jpg](https://static.wixstatic.com/media/2b3baf_2d889e11d25d439eb0783443633c4313~mv2.jpg/v1/fill/w_600,h_416,al_c,q_80,usm_0.66_1.00_0.01,enc_avif,quality_auto/IMG_3404.jpg)
Solving concentration problems
The unit for concentration is mol/dm³ and can be calculated with this equation:
Method 1) use the equations n = m/M and c = n/V
Method 2) C₁V₁ = k C₂V₂ (where k is the mole ratio)
![Screen Shot 2022-04-11 at 2.02.58 PM.png](https://static.wixstatic.com/media/2b3baf_f079c386781749ea9b5903adf45e5ede~mv2.png/v1/fill/w_318,h_68,al_c,q_85,usm_0.66_1.00_0.01,enc_avif,quality_auto/Screen%20Shot%202022-04-11%20at%202_02_58%20PM.png)
![IMG_3405.jpg](https://static.wixstatic.com/media/2b3baf_ae38d0ffb4e841018f7ba3f3dc58b412~mv2.jpg/v1/fill/w_600,h_466,al_c,q_80,usm_0.66_1.00_0.01,enc_avif,quality_auto/IMG_3405.jpg)
![IMG_3406.jpg](https://static.wixstatic.com/media/2b3baf_716daf0089654991b0488de234e9d527~mv2.jpg/v1/fill/w_829,h_489,al_c,q_85,usm_0.66_1.00_0.01,enc_avif,quality_auto/IMG_3406.jpg)
![IMG_3407.jpg](https://static.wixstatic.com/media/2b3baf_fed8cfa3d0b944f09b977fb6f81bae3d~mv2.jpg/v1/fill/w_825,h_460,al_c,q_85,usm_0.66_1.00_0.01,enc_avif,quality_auto/IMG_3407.jpg)
Solving parts per million problems
Parts per million (ppm) is a unit of concentration (mass to mass) → represented as 1g / 10⁶ g
![Screen Shot 2022-04-11 at 2.11.02 PM.png](https://static.wixstatic.com/media/2b3baf_75c7babc9a674a0fa27e8c8cd274432a~mv2.png/v1/fill/w_599,h_389,al_c,q_85,usm_0.66_1.00_0.01,enc_avif,quality_auto/Screen%20Shot%202022-04-11%20at%202_11_02%20PM.png)
Other important calculations:
![Screen Shot 2022-04-11 at 1.48.56 PM.png](https://static.wixstatic.com/media/2b3baf_38ac0368b2944c67844fdcb5f54994a9~mv2.png/v1/fill/w_598,h_161,al_c,q_85,usm_0.66_1.00_0.01,enc_avif,quality_auto/Screen%20Shot%202022-04-11%20at%201_48_56%20PM.png)
In titration, there are two solutions: one solution with a known concentration and volume & one solution with an unknown concentration and volume.
Through titration, we can determine the volume of the unknown solution, and thus calculate its concentration.
Use the C₁V₁ = k C₂V₂ equation.
![Screen Shot 2022-04-11 at 2.01.48 PM.png](https://static.wixstatic.com/media/2b3baf_92346f03507d4a2c98cfa4fa55738ac7~mv2.png/v1/fill/w_288,h_300,al_c,q_85,usm_0.66_1.00_0.01,enc_avif,quality_auto/Screen%20Shot%202022-04-11%20at%202_01_48%20PM.png)