Topic 15. Energetics/thermochemistry HL
15.1 Energy cycles
The Born-Haber Cycle is a diagrammatic representation of the formation of ionic compounds, starting from atoms, moving to gaseous atoms to gaseous ions to a solid compound. It is used to determine lattice enthalpies.
ex) Born-Haber Cycle for NaCl
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atomization of Na
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atomization of Cl
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first ionization of Na
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electron affinity of Cl
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formation of NaCl
Na (s) + ½ Cl2 (g)
Na (g) + ½ Cl2 (g)
Na (g) + Cl (g) → ½ bond enthalpy of Cl2
Na⁺ (g) + Cl (g)
Na⁺ (g) + Cl⁻ (g)
NaCl (s)
![Screen Shot 2022-05-11 at 7.12.37 PM.png](https://static.wixstatic.com/media/2b3baf_6eb0f1630868442d91c119a2ab83df79~mv2.png/v1/fill/w_510,h_248,al_c,q_85,usm_0.66_1.00_0.01,enc_avif,quality_auto/Screen%20Shot%202022-05-11%20at%207_12_37%20PM.png)
From Ms. Fu's powerpoint
![IMG_3589.jpg](https://static.wixstatic.com/media/2b3baf_f9b60b2f67df48b79ff5d3668a2ccc60~mv2.jpg/v1/fill/w_387,h_261,al_c,q_80,usm_0.66_1.00_0.01,enc_avif,quality_auto/IMG_3589.jpg)
The enthalpy of atomization (∆Hºat) is the energy change required to change one mole of atoms from their standard state to a gaseous state
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always endothermic
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ex. M (s) → M (g)
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ex. ½ X₂ (g) → X (g)
Ionization requires energy → endothermic
Electron affinity → exothermic
The lattice enthalpy (∆Hºlat) is the energy required to convert one mole of an ionic substance into gaseous ions
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depends on the strength of the bond:
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magnitude of charge of ions: if |charge|↑ then lattice enthalpy ↑
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size of ions: if size ↑ then lattice enthalpy ↓
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smaller ions have greater attraction because of their higher charge density
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rule of thumb: if the charge is the same, the smaller ion wins
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larger lattice enthalpies → higher melting points (extra energy required to separate oppositely charged ions)
![Screen Shot 2022-05-11 at 7.31.59 PM.png](https://static.wixstatic.com/media/2b3baf_cbd082d13a164531b8c69529aec73ce6~mv2.png/v1/fill/w_307,h_194,al_c,q_85,usm_0.66_1.00_0.01,enc_avif,quality_auto/Screen%20Shot%202022-05-11%20at%207_31_59%20PM.png)
![Screen Shot 2022-05-11 at 7.13.55 PM.png](https://static.wixstatic.com/media/2b3baf_b466faa88ef44a20b7ece4e4af7fe622~mv2.png/v1/fill/w_729,h_406,al_c,q_85,usm_0.66_1.00_0.01,enc_avif,quality_auto/Screen%20Shot%202022-05-11%20at%207_13_55%20PM.png)
From Ms. Fu's powerpoint
Covalent character increases down a group and across a period. Covalent character increases as the difference between experimental and theoretical values of lattice enthalpy increases. (Not that important).
∆Hºsol = ∆Hºlat + ∆Hºhyd
Solvation is when IMFs form between a solvent and solute
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type of ion formed affects the bond strength
The enthalpy of solution (∆Hºsol) is the energy change that occurs when one mole of solute dissolves in excess solvent to form a dilute solution
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type of ion formed affects the bond strength
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can be either + or –
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solid → aqueous
The enthalpy of hydration (∆Hºhyd) is the energy change that occurs when one mole of gaseous ions are added to water to form a dilute solution
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type of ion formed affects the bond strength
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always – because it is exothermic
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gas + water → aqueous
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if the solvent ≠ water → enthalpy of solvation
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∆Hºhyd is greater when...
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size ↓
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charge ↑
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because there is a stronger interaction with polar water molecules
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![Screen Shot 2022-05-11 at 7.48.52 PM.png](https://static.wixstatic.com/media/2b3baf_12c0c9b588984316b3fb2670c5e7dbe6~mv2.png/v1/crop/x_0,y_139,w_1158,h_388/fill/w_442,h_148,al_c,q_85,usm_0.66_1.00_0.01,enc_avif,quality_auto/Screen%20Shot%202022-05-11%20at%207_48_52%20PM.png)
![Screen Shot 2022-05-11 at 7.48.57 PM.png](https://static.wixstatic.com/media/2b3baf_82e8698a83744242b3b6cdd06c7c9724~mv2.png/v1/fill/w_313,h_111,al_c,q_85,usm_0.66_1.00_0.01,enc_avif,quality_auto/Screen%20Shot%202022-05-11%20at%207_48_57%20PM.png)
Same reaction, different way to illustrate.
15.2 Entropy and spontaneity
Entropy (s) is a measure of distribution of total available energy among particles. It measures "how disordered" a system is.
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nature goes towards high entropy
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entropy increases with temperature
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can be determined by the change in the number of gaseous particles
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measured in J/K*mol
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gases have the most entropy, solids have the least
∆Sº = ∑Sº (products) – ∑Sº (reactants)
Gibbs free energy (G) is the energy available to do work.
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if Gº is...
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positive: non-spontaneous reaction
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negative: spontaneous reaction
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zero: in equilibrium
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measured in kJ/K*mol
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must convert entropy to kJ/K*mol before using the following equation:
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∆Gº = ∆Hº – T∆Sº
∆Gº: change in Gibbs free energy (kJ/m0l)
∆H: enthalpy change (kJ/mol)
T: temperature (K)
∆Sº: entropy (convert to kJ/K*mol)
![Screen Shot 2022-05-11 at 8.08.20 PM.png](https://static.wixstatic.com/media/2b3baf_c2815e8a13d24c8780939976ca7e39d6~mv2.png/v1/fill/w_927,h_310,al_c,q_85,usm_0.66_1.00_0.01,enc_avif,quality_auto/Screen%20Shot%202022-05-11%20at%208_08_20%20PM.png)
From Ms. Fu's powerpoint
From Ms. Fu's powerpoint
![Screen Shot 2022-05-11 at 8.08.28 PM.png](https://static.wixstatic.com/media/2b3baf_9c6f6453c91b43b2a424dc04e017d49a~mv2.png/v1/fill/w_672,h_234,al_c,q_85,usm_0.66_1.00_0.01,enc_avif,quality_auto/Screen%20Shot%202022-05-11%20at%208_08_28%20PM.png)
From Ms. Fu's powerpoint
Pearson textbook pg. 253